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-rw-r--r-- | arch/blackfin/lib/udivdi3.S | 375 |

1 files changed, 0 insertions, 375 deletions

diff --git a/arch/blackfin/lib/udivdi3.S b/arch/blackfin/lib/udivdi3.S deleted file mode 100644 index ad1ebee675e1..000000000000 --- a/arch/blackfin/lib/udivdi3.S +++ /dev/null @@ -1,375 +0,0 @@ -/* - * udivdi3.S - unsigned long long division - * - * Copyright 2003-2007 Analog Devices Inc. - * Enter bugs at http://blackfin.uclinux.org/ - * - * Licensed under the GPLv2 or later. - */ - -#include <linux/linkage.h> - -#define CARRY AC0 - -#ifdef CONFIG_ARITHMETIC_OPS_L1 -.section .l1.text -#else -.text -#endif - - -ENTRY(___udivdi3) - R3 = [SP + 12]; - [--SP] = (R7:4, P5:3); - - /* Attempt to use divide primitive first; these will handle - ** most cases, and they're quick - avoids stalls incurred by - ** testing for identities. - */ - - R4 = R2 | R3; - CC = R4 == 0; - IF CC JUMP .LDIV_BY_ZERO; - - R4.H = 0x8000; - R4 >>>= 16; // R4 now 0xFFFF8000 - R5 = R0 | R2; // If either dividend or - R4 = R5 & R4; // divisor have bits in - CC = R4; // top half or low half's sign - IF CC JUMP .LIDENTS; // bit, skip builtins. - R4 = R1 | R3; // Also check top halves - CC = R4; - IF CC JUMP .LIDENTS; - - /* Can use the builtins. */ - - AQ = CC; // Clear AQ (CC==0) - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - DIVQ(R0, R2); - R0 = R0.L (Z); - R1 = 0; - (R7:4, P5:3) = [SP++]; - RTS; - -.LIDENTS: - /* Test for common identities. Value to be returned is - ** placed in R6,R7. - */ - // Check for 0/y, return 0 - R4 = R0 | R1; - CC = R4 == 0; - IF CC JUMP .LRETURN_R0; - - // Check for x/x, return 1 - R6 = R0 - R2; // If x == y, then both R6 and R7 will be zero - R7 = R1 - R3; - R4 = R6 | R7; // making R4 zero. - R6 += 1; // which would now make R6:R7==1. - CC = R4 == 0; - IF CC JUMP .LRETURN_IDENT; - - // Check for x/1, return x - R6 = R0; - R7 = R1; - CC = R3 == 0; - IF !CC JUMP .Lnexttest; - CC = R2 == 1; - IF CC JUMP .LRETURN_IDENT; - -.Lnexttest: - R4.L = ONES R2; // check for div by power of two which - R5.L = ONES R3; // can be done using a shift - R6 = PACK (R5.L, R4.L); - CC = R6 == 1; - IF CC JUMP .Lpower_of_two_upper_zero; - R6 = PACK (R4.L, R5.L); - CC = R6 == 1; - IF CC JUMP .Lpower_of_two_lower_zero; - - // Check for x < y, return 0 - R6 = 0; - R7 = R6; - CC = R1 < R3 (IU); - IF CC JUMP .LRETURN_IDENT; - CC = R1 == R3; - IF !CC JUMP .Lno_idents; - CC = R0 < R2 (IU); - IF CC JUMP .LRETURN_IDENT; - -.Lno_idents: // Idents don't match. Go for the full operation - - - // If X, or X and Y have high bit set, it'll affect the - // results, so shift right one to stop this. Note: we've already - // checked that X >= Y, so Y's msb won't be set unless X's - // is. - - R4 = 0; - CC = R1 < 0; - IF !CC JUMP .Lx_msb_clear; - CC = !CC; // 1 -> 0; - R1 = ROT R1 BY -1; // Shift X >> 1 - R0 = ROT R0 BY -1; // lsb -> CC - BITSET(R4,31); // to record only x msb was set - CC = R3 < 0; - IF !CC JUMP .Ly_msb_clear; - CC = !CC; - R3 = ROT R3 BY -1; // Shift Y >> 1 - R2 = ROT R2 BY -1; - BITCLR(R4,31); // clear bit to record only x msb was set - -.Ly_msb_clear: -.Lx_msb_clear: - // Bit 31 in R4 indicates X msb set, but Y msb wasn't, and no bits - // were lost, so we should shift result left by one. - - [--SP] = R4; // save for later - - // In the loop that follows, each iteration we add - // either Y' or -Y' to the Remainder. We compute the - // negated Y', and store, for convenience. Y' goes - // into P0:P1, while -Y' goes into P2:P3. - - P0 = R2; - P1 = R3; - R2 = -R2; - CC = CARRY; - CC = !CC; - R4 = CC; - R3 = -R3; - R3 = R3 - R4; - - R6 = 0; // remainder = 0 - R7 = R6; - - [--SP] = R2; P2 = SP; - [--SP] = R3; P3 = SP; - [--SP] = R6; P5 = SP; // AQ = 0 - [--SP] = P1; - - /* In the loop that follows, we use the following - ** register assignments: - ** R0,R1 X, workspace - ** R2,R3 Y, workspace - ** R4,R5 partial Div - ** R6,R7 partial remainder - ** P5 AQ - ** The remainder and div form a 128-bit number, with - ** the remainder in the high 64-bits. - */ - R4 = R0; // Div = X' - R5 = R1; - R3 = 0; - - P4 = 64; // Iterate once per bit - LSETUP(.LULST,.LULEND) LC0 = P4; -.LULST: - /* Shift Div and remainder up by one. The bit shifted - ** out of the top of the quotient is shifted into the bottom - ** of the remainder. - */ - CC = R3; - R4 = ROT R4 BY 1; - R5 = ROT R5 BY 1 || // low q to high q - R2 = [P5]; // load saved AQ - R6 = ROT R6 BY 1 || // high q to low r - R0 = [P2]; // load -Y' - R7 = ROT R7 BY 1 || // low r to high r - R1 = [P3]; - - // Assume add -Y' - CC = R2 < 0; // But if AQ is set... - IF CC R0 = P0; // then add Y' instead - IF CC R1 = P1; - - R6 = R6 + R0; // Rem += (Y' or -Y') - CC = CARRY; - R0 = CC; - R7 = R7 + R1; - R7 = R7 + R0 (NS) || - R1 = [SP]; - // Set the next AQ bit - R1 = R7 ^ R1; // from Remainder and Y' - R1 = R1 >> 31 || // Negate AQ's value, and - [P5] = R1; // save next AQ - BITTGL(R1, 0); // add neg AQ to the Div -.LULEND: R4 = R4 + R1; - - R6 = [SP + 16]; - - R0 = R4; - R1 = R5; - CC = BITTST(R6,30); // Just set CC=0 - R4 = ROT R0 BY 1; // but if we had to shift X, - R5 = ROT R1 BY 1; // and didn't shift any bits out, - CC = BITTST(R6,31); // then the result will be half as - IF CC R0 = R4; // much as required, so shift left - IF CC R1 = R5; // one space. - - SP += 20; - (R7:4, P5:3) = [SP++]; - RTS; - -.Lpower_of_two: - /* Y has a single bit set, which means it's a power of two. - ** That means we can perform the division just by shifting - ** X to the right the appropriate number of bits - */ - - /* signbits returns the number of sign bits, minus one. - ** 1=>30, 2=>29, ..., 0x40000000=>0. Which means we need - ** to shift right n-signbits spaces. It also means 0x80000000 - ** is a special case, because that *also* gives a signbits of 0 - */ -.Lpower_of_two_lower_zero: - R7 = 0; - R6 = R1 >> 31; - CC = R3 < 0; - IF CC JUMP .LRETURN_IDENT; - - R2.L = SIGNBITS R3; - R2 = R2.L (Z); - R2 += -62; - (R7:4, P5:3) = [SP++]; - JUMP ___lshftli; - -.Lpower_of_two_upper_zero: - CC = R2 < 0; - IF CC JUMP .Lmaxint_shift; - - R2.L = SIGNBITS R2; - R2 = R2.L (Z); - R2 += -30; - (R7:4, P5:3) = [SP++]; - JUMP ___lshftli; - -.Lmaxint_shift: - R2 = -31; - (R7:4, P5:3) = [SP++]; - JUMP ___lshftli; - -.LRETURN_IDENT: - R0 = R6; - R1 = R7; -.LRETURN_R0: - (R7:4, P5:3) = [SP++]; - RTS; -.LDIV_BY_ZERO: - R0 = ~R2; - R1 = R0; - (R7:4, P5:3) = [SP++]; - RTS; - -ENDPROC(___udivdi3) - - -ENTRY(___lshftli) - CC = R2 == 0; - IF CC JUMP .Lfinished; // nothing to do - CC = R2 < 0; - IF CC JUMP .Lrshift; - R3 = 64; - CC = R2 < R3; - IF !CC JUMP .Lretzero; - - // We're shifting left, and it's less than 64 bits, so - // a valid result will be returned. - - R3 >>= 1; // R3 now 32 - CC = R2 < R3; - - IF !CC JUMP .Lzerohalf; - - // We're shifting left, between 1 and 31 bits, which means - // some of the low half will be shifted into the high half. - // Work out how much. - - R3 = R3 - R2; - - // Save that much data from the bottom half. - - P1 = R7; - R7 = R0; - R7 >>= R3; - - // Adjust both parts of the parameter. - - R0 <<= R2; - R1 <<= R2; - - // And include the bits moved across. - - R1 = R1 | R7; - R7 = P1; - RTS; - -.Lzerohalf: - // We're shifting left, between 32 and 63 bits, so the - // bottom half will become zero, and the top half will - // lose some bits. How many? - - R2 = R2 - R3; // N - 32 - R1 = LSHIFT R0 BY R2.L; - R0 = R0 - R0; - RTS; - -.Lretzero: - R0 = R0 - R0; - R1 = R0; -.Lfinished: - RTS; - -.Lrshift: - // We're shifting right, but by how much? - R2 = -R2; - R3 = 64; - CC = R2 < R3; - IF !CC JUMP .Lretzero; - - // Shifting right less than 64 bits, so some result bits will - // be retained. - - R3 >>= 1; // R3 now 32 - CC = R2 < R3; - IF !CC JUMP .Lsignhalf; - - // Shifting right between 1 and 31 bits, so need to copy - // data across words. - - P1 = R7; - R3 = R3 - R2; - R7 = R1; - R7 <<= R3; - R1 >>= R2; - R0 >>= R2; - R0 = R7 | R0; - R7 = P1; - RTS; - -.Lsignhalf: - // Shifting right between 32 and 63 bits, so the top half - // will become all zero-bits, and the bottom half is some - // of the top half. But how much? - - R2 = R2 - R3; - R0 = R1; - R0 >>= R2; - R1 = 0; - RTS; - -ENDPROC(___lshftli) |